That would allow for like, 2 trillion devices? Feels like a bandaid, my dude. Next you’re gonna suggest a giant ice cube in the ocean once a year to stop global warming.
Please don’t. Use regex to find something that looks like an IP then build a real parser. This is madness, its’s extremely hard to read and a mistake is almost impossible to spot. Not to mention that it’s slow.
Just parse [0-9]{1,3}.[0-9]{1,3}.[0-9]{1,3}.[0-9]{1,3} using regex (for v4) and then have some code check that all the octets are valid (and store the IP as a u32).
Ok. This covers every ipv6 and ipv4 address.
“^\s*((([0-9A-Fa-f]1,4}:){7}([0-9A-Fa-f]{1,4}:)6}(:[0-9A-Fa-f]{1,4})|:))|(([0-9A-Fa-f]1,4}:){5}(((:[0-9A-Fa-f]{1,4}){1,2}))|:))|(([0-9A-Fa-f]1,4}:){4}(((:[0-9A-Fa-f]{1,4}){1,3}))?:((25[0-5]|2[0-4][0-9]|1[0-9][0-9]|[1-9]?[0-9])(.(25[0-5]|2[0-4][0-9]|1[0-9][0-9]|[1-9]?[0-9]))3})):)3}(((:[0-9A-Fa-f]{1,4}){1,4}))0,2}:((25[0-5]))|:))|(([0-9A-Fa-f]1,4}:){2}(((:[0-9A-Fa-f]{1,4}){1,5}))0,3}:((25[0-5]))|:))|(([0-9A-Fa-f]1,4}:){1}(((:[0-9A-Fa-f]{1,4}){1,6}))0,4}:((25[0-5]))|:))|(:(((:[0-9A-Fa-f]1,4}){1,7}))0,5}:((25[0-5]))|:)))(%.+)?\s*$”
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IPv6 was a mistake. We should have just added an addition octet
They played us for absolute fools!
That would allow for like, 2 trillion devices? Feels like a bandaid, my dude. Next you’re gonna suggest a giant ice cube in the ocean once a year to stop global warming.
And nuke the hurricanes
So add two more octets:
Moat companies will still just use something like 10.0.13.37.0.1
IPv6 is not made with internal networks in mind lol
heared of ipv5?
Plus the MAC address
I knew there would be someone with the regex.
It’s always a treat to debug a regex of that size.
You’re more of a perl programmer than network engineer :P
*exits the room*
https://imgs.xkcd.com/comics/perl_problems.png
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Please don’t. Use regex to find something that looks like an IP then build a real parser. This is madness, its’s extremely hard to read and a mistake is almost impossible to spot. Not to mention that it’s slow.
Just parse [0-9]{1,3}.[0-9]{1,3}.[0-9]{1,3}.[0-9]{1,3} using regex (for v4) and then have some code check that all the octets are valid (and store the IP as a u32).
And dupe check. 0.0.0.0 and 000.000.000.000 may both be valid, but they resolve the same
.*
Technically, this one also matches everything: